show that ∆AOB=~∆DOC
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In ∆AOB and DOC
angle CDO = angle BAO .......alternate angles
angle AOB = angle COD......vertically opposite angles
angle OCD= angle OBA........alternate angles
therefore ∆AOB =~∆DOC .....by AAA test
angle CDO = angle BAO .......alternate angles
angle AOB = angle COD......vertically opposite angles
angle OCD= angle OBA........alternate angles
therefore ∆AOB =~∆DOC .....by AAA test
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