Question

show that ar AQC= at ABC =2:5

Answer 1

$\frac{area \: of \: apc}{area \: of \: abc} = \frac{2}{3}.................(1) \\ \frac{area \: of \: apc}{area \: of \: aqc} = \frac{5}{3} .................(2) \\ eq \: (1) \div (2) \\ \frac{area \: of \: aqc}{area \: of \: abc} = \frac{2}{5}$