Question

show that are given gun will shoot three times as high when elevated at an angle of 60° when fired at an angle of 30 degree but will carry the same distance on a horizontal plane.
Guys please solve as I don't want to get punishment.
Please... Please

Answer 1

Here is your answer dear frnd⤵⤵⤵⤵⤵⤵


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✔Range = U2 sin 2​θ / g

⏩for θ = 60 , Range will be 

= U2 sin 120 / g

= U2 √3 / 2g   ( sin 120 = √3 / 2 )

➡√3 U2 / 2g

⏩Now for θ = 30 , Range will be

U2 sin 60 / g

U2 √3 / 2g  ( sin 60 = √3 / 2 )

➡√3 U2 / 2g

Hence range for both the angles are same.



❤❤Hope it will help you❤❤



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Answer 2

Answer:

Range = U2 sin 2θ / g

for θ = 60 , Range will be

= U2 sin 120 / g

= U2 √3 / 2g ( sin 120 = √3 / 2 )

= √3 U2 / 2g

Now for θ = 30 , Range will be

U2 sin 60 / g

U2 √3 / 2g ( sin 60 = √3 / 2 )

√3 U2 / 2g

Hence range for both the angles are same