Show that AUB(A union B) = A Intersection B implies A=B.
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hey
let A=B
A = {1,2}
B = {1,2}
AUB = {1,2}
A intersection B = {1,2}
therefore AUB(A union B) = A Intersection B implies A=B.
let A=B
A = {1,2}
B = {1,2}
AUB = {1,2}
A intersection B = {1,2}
therefore AUB(A union B) = A Intersection B implies A=B.
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