Show that,
bc(b-c) + ca(c-a) + ab(a-b) = [-(b-c) (c-a) (a-b) ]
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Answered by
2
Answer:
there you go .
prove that LHS=RHS
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Answered by
1
Answer:
L.H.S=bc(b-c) + ca(c-a) + ab(a-b
=a^2(b-c)+b^2(c-a)+c^2(a-b)
=a^2*b-a^2*c+a*c^2+b^2*c-b^2*a-b*c^2
=-(abc-a^2*b-a^2*c+a^2*c-b^2*c+b^2*a+b*c^2-abc)
=[-(b-c) (c-a) (a-b) ]=R.H.S
Step-by-step explanation:
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