Question

Show that,
bc(b-c) + ca(c-a) + ab(a-b) = [-(b-c) (c-a) (a-b) ]​

Answer 1

Answer:

there you go .

prove that LHS=RHS

Answer 2

Answer:

L.H.S=bc(b-c) + ca(c-a) + ab(a-b

=a^2(b-c)+b^2(c-a)+c^2(a-b)

=a^2*b-a^2*c+a*c^2+b^2*c-b^2*a-b*c^2

=-(abc-a^2*b-a^2*c+a^2*c-b^2*c+b^2*a+b*c^2-abc)

=[-(b-c) (c-a) (a-b) ]​=R.H.S

Step-by-step explanation: