Math, asked by thaneeshkumar18, 1 month ago

Show that cos(π/15)cos(2π/15)cos(3π/15)cos(4π/15)cos(5π/15)cos(6π/15)cos(7π/15) = 1/128

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Answered by CottonCandyGirl

Answer:

Show that cos(π/15)cos(2π/15)cos(3π/15)cos(4π/15)cos(5π/15)cos(6π/15)cos(7π/15) = 1/128Show that cos(π/15)cos(2π/15)cos(3π/15)cos(4π/15)cos(5π/15)cos(6π/15)cos(7π/15) = 1/128Show that cos(π/15)cos(2π/15)cos(3π/15)cos(4π/15)cos(5π/15)cos(6π/15)cos(7π/15) = 1/128

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