Question

Show that cos ²(45°+ϴ)+cos²(45° - ϴ) / tan(60° +ϴ) tan(30 - ϴ) = 1
(Class 10 Maths Sample Question Paper)

Answer 1

SOLUTION:
LHS = cos ²(45°+ϴ) + cos²(45° - ϴ) / tan(60° +ϴ) tan(30 - ϴ) = 1
= sin²[90° - (45°+ϴ)]+ cos²(45° - ϴ) / cot [90° - (60° +ϴ)] tan(30 - ϴ)
[ Cosϴ= sin(90°-ϴ) & cot ϴ= tan (90°-ϴ)]
= sin²(45°-ϴ)+ cos²(45° - ϴ) / cot 30° - ϴ)] tan(30° - ϴ)
= 1/1 = RHS
[ sin²ϴ + cos²ϴ= 1 and tanϴcotϴ=1]

HOPE THIS WILL HELP YOU...

Answer 2

Answer:

here is your answer..........