Math, asked by msm91, 10 months ago

Show that cos 32.cos 58-sin 32.sin58=0

Answers

Answered by vipul03

1

Cos32 cos(90-58 ) - sin32 sin(90-58

Cos32 Sin32 -Sin32 cos32

on subtracting we will get 0

Answered by kingcross434

0

Answer:

Cos 32 =Sin( 90-32)

Sin58

Sin58.cos58-sin32=cos(90-32)

Cos58

Now

Sin58.cos58-cos58.sin58

Not cut sin58 with another sin58 and cos58 with another cos58

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