Show that cos(∅-40°)=sin(∅+50°)
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= sin(50+θ) - cos(40-θ)
= sin(50+θ) - sin[90-(40-θ)]
= sin(50+θ) - sin(90-40+θ)
= sin(50+θ) - sin(50+θ)
= 0
= sin(50+θ) - sin[90-(40-θ)]
= sin(50+θ) - sin(90-40+θ)
= sin(50+θ) - sin(50+θ)
= 0
Lilly111:
how csn i do that?
thank u!!
you're welcome!!
by clicking the options tap of my answer you can!
tab*
like after one more answer comes you can see an option called mark as brainliest then you can choose it! thank you!! :)
i don't see any option other than 'report answer'. can you be more specific? thnx
I mean if someone else would have answered too then you could have got that option.. but now here only I've answered.. so the option won't show.. so its okay! anyway any doubts do ask!
Thank you so much! :-)
you're welcome! :)
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