Show that cos A + cos B + cos C = 1 +
R
Answers
Answered by
2
Answer:
Step-by-step explanation:
cosA+cosB+cosC
=1+4sin(
2
A
)sin(
2
B
)sin(
2
C
)
=1+
R
(4Rsin(
2
A
)sin(
2
B
)sin(
2
C
))
=1+
R
r
Answered by
0
Step-by-step explanation:
cosA+cosB+cosC
1+4sin(A/2)*sin(B/2)*sin(C/2)
1+[4rsin(A/2)*sin(B/2)*sin(C/2)]/R
1+r/R
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