Question

show that cos square 45 degree + theta + cos square 45 degree minus theta by tan square 60 degree + theta into tan square 30 degree minus theta is equal to 1​

Answer 1

To prove :

[cos²(45+∅) + cos²(45-∅) ] / tan(60+∅)×tan(30-∅)   =1

Proof :

• L.H.S = [cos²(45+∅) + cos²(45-∅) ] / tan(60+∅)×tan(30-∅)

         =[cos²(45+∅) + sin²(90 -(45+∅)) ] / tan(60+∅)×cot(90-(60+∅) )

                                         [CosA=Sin(90-A) ; TanA=Cot(90-A)]

        =[cos²(45+∅) + sin²(45+∅) ] / tan(60+∅)×cot(60+∅)

                                       [Cos²A+Sin²A = 1   ; TanA.CotA=1]

        = 1/1

        =1

• L.H.S = R.H.S

• [cos²(45+∅) + cos²(45-∅) ] / tan(60+∅)×tan(30-∅)   =1

Answer 2

Hope it's help you

plz follow me

mark as a brainlist