show that: cos teta.[cos teta sin teta/ - sin teta cos teta] + sin teta. [ sin teta - cos teta/ cos teta sin teta]=[1 0/0 1]
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Step-by-step explanation:
Prove : sinθ(90∘−θ−cosθcos(90∘−θ)=0.
Medium
We know;
sin(90 ∘−θ)=cosθandcos(90 ∘−θ)=sinθ
L.H.S=sinθ sin(90 ∘−θ)−cosθ cos(90∘−θ)=sinθ cosθ−cosθ sinθ=0=R.H.S
∵L.H.S=R.H.S
sinθ sin(90∘−θ)−cosθ cos(90∘−θ)=0
Hence proved
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