Show that cos10°cos50°cos60°cos70°=√3/16
Answers
Answered by
1
Answer:
cos60cos10cos50cos70 = (1/2)[cos10cos70]cos50
= (1/2)(1/2)(cos80+cos60)cos50
= (1/4)(cos80cos50+(1/2)cos50)
= (1/4)((1/2)(cos130+cos30)+(1/2)cos50)
= (1/8)(cos30-cos50+cos50)
= (1/8)cos30
= (1/16)sqrt(3).
Mark me brilliant and follow me
Answered by
0
Answer:
plzz mark my ans as braiblieat
Step-by-step explanation:
cos60cos10cos50cos70 = (1/2)[cos10cos70]cos50
= (1/2)(1/2)(cos80+cos60)cos50
= (1/4)(cos80cos50+(1/2)cos50)
= (1/4)((1/2)(cos130+cos30)+(1/2)cos50)
= (1/8)(cos30-cos50+cos50)
= (1/8)cos30
= (1/16)sqrt(3).
10
Similar questions