show that cos135°sin45°-sin135cos45°+cos180°=-2
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Using the identity,
sin(A-B) = sinAcosB - CosAsinB,
cos135sin45 - sin135cos45 = sin(45-135) = sin(-90) = -1
We know cos180 = -1
Therefore answer is -1 -1 = -2
sin(A-B) = sinAcosB - CosAsinB,
cos135sin45 - sin135cos45 = sin(45-135) = sin(-90) = -1
We know cos180 = -1
Therefore answer is -1 -1 = -2
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