Question

Show that:
COS2 (45° + ) + cos2 (45° - 0)
tan (60° + 0) tan (30° – 0) = 1.​

Answer 1

Answer:

$hey \: mate \: your \: answer \: is \: here... \\ \cos(45) = 1 \div \sqrt{2} \\ tan(60) = \sqrt{3} \\ \tan(30) = 1 \div \sqrt{3} \\ \\ 2 \times 1 \div 2 + 2 \times 1 \div 2 \times \sqrt{3} \times 1 \div \sqrt{3} \\ = 1 \\ so \\ lhs = rhs \\ hence \: proved$