show that cos²a + cos² (a+ b) - 2cos a cos b cos (a+ b) = sin²b
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Answered by
1
LHS,
Cos^2A +cos(A+B) [Cos(A+B) - 2cosA cosB ]
Cos^2A+cos(A+B) [ cosA cosB - sinA sin B -2 cosA cosB]
Cos^2A - cos (A+B) [ cos (A-B) ]
Cos^2A -( cos^2A -sin^2B)
Sin^2B = RHS
Hence proved
Answered by
3
Step-by-step explanation:
hope it helps you。◕‿◕。
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