Math, asked by guygamechanger1, 5 months ago

Show that cos36° cos54° – sin36° sin54° = 0.

Answers

Answered by Anonymous

16

$\huge{\mathbb{\red{ANSWER:-}}}$

(Cos36° Cos54° - Sin36° Sin54°)

$\sf{(CosACosB - SinASinB) = Cos(A + B)}$

= Cos(36° + 54°)

= Cos90°

= 0

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