Math, asked by sahilgod6087, 1 year ago

Show that cosec(270-A)+cosec(90-A)+sec(90-A)+sec(270-A)=0

Answers

Answered by Lsantosh
2
Cosec(270-A) = -secA
Cosec (90-A) = SecA
Sec (90-A) = cosecA
Sec (270-A) = -cosecA

Cosec(270-A) +Cosec (90-A) +Sec (90-A) + Sec (270-A)

= -secA+SecA+cosecA-cosecA
= 0

Hence proved
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