Math, asked by preciousminmin, 10 months ago

Show that cosec square ø - tan square (90-ø) = sin square ø +sin square (90-ø)

Answers

Answered by arvindkakade
1
Cosec²∅ - tan²(90-∅) = LHS

1/sin²∅ - cot²∅

1/sin²∅ - cos²∅/sin²∅

1-cos²∅/sin²∅

sin²∅ / sin²∅

1

RHS = sin²∅ + sin²(90-∅)

sin²∅ + cos²∅

1

hence LHS = RHS
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