Question

show that cosh x + cosh (x + y) + cosh (x + 2y) +....n terms =
cosh [x +((n − 1)/2)y] sinh (ny/2)
sinh (1/2)​

Answer 1

Answer:

(e2x − e−2x) = sinh 2x, which is what we wanted to achieve. ... In fact the hyperbolic functions are very closely related to the trigonometric functions, and sinh x and cosh x are sometimes called the hyperbolic sine and hyperbolic cosine functions.