show that
cosx + sin(270°+x) -sin(270-x) + cos(180°+x) =0
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Answer:
The explanation has been given on step-by-step explanation.
Step-by-step explanation:
cosx + sin (270°+x) - sin (270°-x) + cos (180°+x)
= cosx + sin (3π+x) - sin (3π-x) + cos (2π+x)
= cosx - sinx + sinx - cosx
= 0
So, L.H.S = R.H.S
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