Question

show that
cosx + sin(270°+x) -sin(270-x) + cos(180°+x) =0​

Answer 1

Answer:

The explanation has been given on step-by-step explanation.

Step-by-step explanation:

cosx + sin (270°+x) - sin (270°-x) + cos (180°+x)

= cosx + sin (3π+x) - sin (3π-x) + cos (2π+x)

= cosx - sinx + sinx - cosx

= 0

So, L.H.S = R.H.S