show that cot thita + tan thita = sec thita.cosec thita
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Answer:
cot thita + tan thita = sec thita.cosec thita
Step-by-step explanation:
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Answered by
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Answer:
cot0 + tan0= sec0* cosec0
cos/sin0+sin/cos0 = sec0*cosec0
cos^2 thita + sin^2 thita(whole divided by) / sin0*cos0
=1/1/cosec0*1/sec0
= 1*cosec0*sec0
=cosec0*sec0
Step-by-step explanation:
in this answer I put thita in 0 mark and square is written in^2 this type
tan0 have two formulas 1) is 1/cot0 and 2) is sin/cos
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