show that cot0+tan0=sec0 cosec0
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Answer: let 0 =some angle
Step-by-step explanation:
Cot0+tan0=cos0/sin0+sin0/cos0
= (Cos^2o-sin^2o)/sinocoso
= 1-2sin^2o/sinocoso
= Coseco seco-2sino/coso
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