Question

Show that cot2x cot3x – cot2x cot5x - cot3xcot5x =1




don't spam please​

Answer 1

Answer

cot x cot 2x - cot 2x cot 3x - cot 3x cot 4x

= cot x cot 2x - cot 3x (cot 2x+ cot x)

= cot x cot 2x - cot (2x+x)(cot 2x+ cot x)

[ as cot(A+B)=

cotAcotB

cotAcotB−1

]

= cot x cot 2x-(

cotx+cot2x

cot2xcotx−1

)(cot 2x+ cot x)

= cot x cot 2x- (cot 2x cot x-1)

= cot x cot 2x- cot 2x cot x+1

= 1

Hence, proved

hope it helps dear

if found helpful mark it as brainiliest and follow pl

trigonometry baffled mee too at first

Answer 2

Answer

cot x cot 2x - cot 2x cot 3x - cot 3x cot 4x

= cot x cot 2x - cot 3x (cot 2x+ cot x)

= cot x cot 2x - cot (2x+x)(cot 2x+ cot x)

[ as cot(A+B)=

cotAcotB

cotAcotB−1

]

= cot x cot 2x-(

cotx+cot2x

cot2xcotx−1

)(cot 2x+ cot x)

= cot x cot 2x- (cot 2x cot x-1)

= cot x cot 2x- cot 2x cot x+1

= 1

Hence, proved

hope it helps dear

if found helpful mark it as brainiliest and follow pl

trigonometry baffled mee too at first