SHOW THAT cotA+cotB+cotC=√3 in equilateral triangle
Answers
Answered by
2
Answer:
Hey friend answer is with the attachment.
Attachments:
Answered by
2
Answer:
In an equilateral triangle, A = B = C = 60°
So, cotA = cotB = cotC
=> cotA + cotB + cotC = 3cotA = 3cot60°
As cot60° = 1/√3 ,
3cot60° = 3(1/√3) = 3/√3 = √3
Therefore cotA + cotB + cotC = √3 in an equilateral triangle
Similar questions