Question

show that cotA+tanB=secA cosecB​

Answer 1

Answer:

cosecA+secA=cosecB+secB  

=>     cosecA−cosecB=secA−secB

=>     1sinA−1sinB=1cosA−1cosB

=>     sinB−sinAsinA.sinB=cosB−cosAcosA.cosB

=>     2sinB−A2cosB+A2sinA.sinB=2sinB−A2sinB+A2cosA.cosB

=>     cosB+A2sinB+A2=sinA.sinBcosA.cosB

=>     cotB+A2=tanA.tanB

=>     tanA.tanB=cotB+A2