Math, asked by bindunppn7427, 18 days ago

Show that cube roots of unity form an abelian group

Answers

Answered by bijo7979
2

Step-by-step explanation:

If for all a belonging to G ,there exists s a b such that a*b=e, then b is called the inverse of a. Clearly , Inverse of 1 is 1, Inverse of ω is ω² and Inverse of ω² is ω. Since, all 4 properties of group are satisfied G is a group. ... Thus, cube roots of unity form a finite abelian group under multiplication.

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