Question

show that delta=r1r2 root of 4R-r1-r2/r1+r2
​

Answer 1

Answer:

As r

1

,r

2

,r

3

are roots of x

3

+lx

2

+mx+n=0

r

1

+r

2

+r

3

=−l

Using r

1

=

s−a

Δ

,r

2

=

s−b

Δ

,r

3

=

s−c

Δ

,r=

s

Δ

We get

r

1

+r

2

+r

3

−r=

s−a

Δ

+

s−b

Δ

+

s−c

Δ

−

s

Δ

=4R

⇒r

1

+r

2

+r

3

=4R+r⇒l=−(4R+r)