Question

Show that determinant 1 a bc
1 b .ca
1 c ab
=(a-b)(b-c)(c-a)

Answer 1

Answer:

(bc-ca)(ca-ab)(ab-bc)

bc-ca+ca-ab+ab-bc

=0

Answer 2

Answer:

1(ab2-ac2)-a(ab-ac)+bc(c-b)=ab2-ac2-a2b+a2c+bc2-b2c.

if you factorise it you will get the required answer