Question

show that diagonals of a square are equal and bisect each other at right angle?​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given that ABCD is a square.

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.Proof:

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.Proof: (i) In a ΔABC and ΔBAD,

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.Proof: (i) In a ΔABC and ΔBAD,AB=AB ( common line)

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.Proof: (i) In a ΔABC and ΔBAD,AB=AB ( common line)BC=AD ( opppsite sides of a square)

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.Proof: (i) In a ΔABC and ΔBAD,AB=AB ( common line)BC=AD ( opppsite sides of a square)∠ABC=∠BAD ( = 90° )

Given that ABCD is a square.To prove : AC=BD and AC and BD bisect each other at right angles.Proof: (i) In a ΔABC and ΔBAD,AB=AB ( common line)BC=AD ( opppsite sides of a square)∠ABC=∠BAD ( = 90° )ΔABC≅ΔBAD( By SAS property)

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