Show that diagonals of parallelogram divide it into four Triangles having equal area
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Given:- ABCD is a //gm.
To prove:- ΔAOB ≅ ΔBOC ≅ ΔCOD ≅ ΔDOA
Proof:- In ΔAOB & ΔCOD
LBAO = LDCO (alternate interior angle)
AB = CD (opp. sides are equal)
LABO = LCDO (alternate interior angle)
Therefore, ΔAOB≅ ΔCOD by AAS Congruence criterion.
Similarly,
ΔAOB ≅ ΔBOC ≅ ΔCOD ≅ ΔDOA
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