Question

show that difference in tension at highest and lowest position is 6 mg ​

Answer 1

Answer:

here, v = √(gh) it is velocity at uttermost position in case of string. ... here, v = √(5gh), it is velocity at Lowest position in case of string. so, T' - mg = 5mgh , T' = 6mg. now, difference in tension at lowest and uttermost point for a particle performing vertical circular motion = T' - T = 6mg.

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