Show that each angle of a rectangle is a right angle
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Let, ABCD be a rectangle.
We have to prove that ∠A=∠B=∠C=∠D=90
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We know that a rectangle is parallelogram where its one angle is 90
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.
Let us assume ∠A=90
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Now,
AD∥BC[oppositesidesofaparallelogramareparallel]
And AB is transversal.
So, ∠A+∠B=180
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[interioranglesonthwsamwsideofatransversalaresupplementary]
⇒90
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+∠B=180
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⇒∠B=90
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Again, we know that opposite angles of a parallelogram are equal.
∴∠C=∠A and ∠D=∠B
∴∠C=90
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and ∠D=90
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∴∠A=∠B=∠C=∠D=90
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Hence, it is proved that ABCD is a rectangle.
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