show that each angle of a rectangle is a right angle
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Let ABCD be a rectangle.
We have to prove that <A=<B=<C=<D
We know that a rectangle is parallelogram
Let us assume <A=90°
Now,
AD||BC [opposite sides of a parallelogram]
And AB s transversal.
So<A+<B=
180° [interior of the same]
=>90°+<B=180°
=><B=90°
Again we know that opposite angles are parallel.
<C=<A and <D=<B
<C=90°and <D=90°
<A=<B=<C=<D= 90°
Hence,it is proved that ABCD is a rectangle.
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here's your answer...hope it helps
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