Question

show that each of the following equations has real roots, and solve each by using the quadratic formula: x^2+x+2=0​

Answer 1

Answer:

x² + x + 2

a= 1 , b = 1 , c= 2

Quadratic formula :-

$\frac{ - b \binom + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \frac{ - 1 \binom{ + }{ - } \sqrt{1 - 8} }{2} \\ \\ \frac{ - 1 \binom{ + }{ - } \sqrt{ - 7} }{2}$

Step-by-step explanation:

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Answer 2

Answer:

x² + x + 2

a= 1 , b = 1 , c= 2

Quadratic formula :-

\begin{gathered} \frac{ - b \binom + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \frac{ - 1 \binom{ + }{ - } \sqrt{1 - 8} }{2} \\ \\ \frac{ - 1 \binom{ + }{ - } \sqrt{ - 7} }{2} \end{gathered}

2a

−b(

−

+

)

b

2

−4ac

2

−1(

−

+

)

1−8

2

−1(

−

+

)

−7

Step-by-step explanation:

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