Question

Show that each of the following fractions is in the simplest form (i)8/11 (ii) 9/14 (iii) 25/36 (iv) 8/15 (v)21/10​

Answer 1

Step-by-step explanation:

i.8/11=8/11

ii. 9/14=9/14

iii.25/36=25/36

iv.8/15=8/15

v.21/10=(10×2+1)in mixed fraction.

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Answer 2

Answer:

The fractions are  $\frac{8}{11}$, $\frac{9}{14}$, $\frac{25}{36}, \frac{8}{15}, \frac{21}{10}$ in the simplest form

Step-by-step explanation:

Given fractions are

$\frac{8}{11}$, $\frac{9}{14}$, $\frac{25}{36}, \frac{8}{15}, \frac{21}{10}$

To prove,

The given fractions are in the simplest form

Recall the concept:

A fraction is said to be in its simplest form if there is a common factor between the numerator and denominator of the fraction other than 1.

That is the numerator and denominator of the fraction are co-primes.

Solution:

(i) In the fraction $\frac{8}{11}$, 8 and 11 are coprime, they have no other common factor other than 1. Hence the fraction  $\frac{8}{11}$ is in the simplest form.

(ii) In the fraction $\frac{9}{14}$, 9 and 14 are coprime, they have no other common factor other than 1. Hence the fraction  $\frac{9}{14}$ is in the simplest form.

(iii) In the fraction $\frac{25}{36}$, 25 and 36 are coprime, they have no other common factor other than 1. Hence the fraction  $\frac{25}{36}$  is in the simplest form.

(iv) In the fraction $\frac{8}{15}$, 8 and 15 are coprime, they have no other common factor other than 1. Hence the fraction $\frac{8}{15}$ is in the simplest form.

(v) In the fraction $\frac{21}{10}$, 21 and 10 are coprime, they have no other common factor other than 1. Hence the fraction $\frac{21}{10}$ is in the simplest form.

Given fractions are  $\frac{8}{11}$, $\frac{9}{14}$, $\frac{25}{36}, \frac{8}{15}, \frac{21}{10}$ in the simplest form

Hence proved

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