Question

show that each of the following number is a perfect square . In each case find the number whose square is the given number ( i) 2025 ii) 6561 iii) 38416


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Answer 1

i) 2025 = 3 x 3 x 3 x 3 x 5 x 5 {As all the numbers r in pair, it is a perfect ²}

√2025 = 3*3*5

√2025 = 45

ii) 6561 = 3*3*3*3*3*3*3*3

√6561 = 3*3*3*3

√6561 = 81

iii) 38416 = 2*2*2*2*7*7*7*7

√38416 = 2*2*7*7

√38416 = 196

Answer 2

Answer:

√2025=45

√6561=81

√38416=196

Step-by-step explanation:

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