Question

show that equation 2x^4+6x+7=0 has no real root

Answer 1

Answer:

D < 0

Step-by-step explanation:

Given a quadratic equation such that,

$2 {x}^{2} + 6x + 7 = 0$

Here, we have,

• a = 2
• b = 6
• c = 7

Now, to show that there is no real roots.

We know that, for a quadratic equation, if Descriminant is less than zero, then there is no real roots.

Let the Descriminant be denoted by 'd'.

Also, we know that,

D = b^2 - 4ac

Substituting the values,

Therefore, we will get,

=> D = 6^2 - 4(2)(7)

=> D = 36 - 56

=> D = -20

Clearly, We have,

=> D < 0

Hence, there is no real roots.

Thus, proved.

Answer 2

Answer:

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