Question

show that equation of line passing through the point acos^3 a,a sin^3a perpendicular to linexseca + ycosec a = a is x cos 2a​

Answer 1

Answer:

If 2 cos2A= √3andA is acute, find.

Step-by-step explanation:

Given 2 cos 2 A=√3 The equation ca be

written as :

cos 2 A=√3/2

Since A is acute <A <90°

25=cos -(√3/2)

So

<br />A = 30°

<br/> A = 15°