Question

show that equation t=2pi l/g is dimensionally correct
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Answer 1

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$t \: = \: 2\pi \: \sqrt{ \frac{l}{g} }$

T is the time period.

L is the length is the pendulum.

g is the acceleration caused by gravity.

$(t) \: = \: {t}^{ - 1}$

$2\pi \: is \: dimensionless.$

$( \sqrt{ \frac{l}{g} } ) = \: {t}^{ - 1}$

Hence, the given equation is dimensionally correct.