Physics, asked by preetkajal01, 3 days ago

show that escape velocity is forty one percent more than orbital velocity. ​

Answers

Answered by jolysanthosh57
0

Explanation:

The escape velocity is a multiplicative factor greater than the orbital velocity: v = sqrt(2GM/r) (escape velocity = sqrt(2) * orbital velocity) If an object achieves escape velocity, it leaves its orbit and is no longer gravitationally bound to the object it was orbiting.

Answered by llshawnxkookiell
0

Answer:

Escape Velocity =

r

2GM

, where G is Gravitational constant, M is the mass of the planet and r is the radius of the orbit

Orbital Velocity =

r

GM

Hence, the ratio of Escape velocity and Orbital velocity is

2

.

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