show that escape velocity is forty one percent more than orbital velocity.
Answers
Answered by
0
Explanation:
The escape velocity is a multiplicative factor greater than the orbital velocity: v = sqrt(2GM/r) (escape velocity = sqrt(2) * orbital velocity) If an object achieves escape velocity, it leaves its orbit and is no longer gravitationally bound to the object it was orbiting.
Answered by
0
Answer:
Escape Velocity =
r
2GM
, where G is Gravitational constant, M is the mass of the planet and r is the radius of the orbit
Orbital Velocity =
r
GM
Hence, the ratio of Escape velocity and Orbital velocity is
2
.
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