Question

show that every even positive integer is of the form 6q or 6q+2 or 6q+4​

Answer 1

Step-by-step explanation:

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Let ‘a’ be any positive even integer and ‘b= 6’.

Therefore, a = 6q +r, where 0 ≤ r < 6.

Now, by placing r = 0, we get, a = 6q + 0 = 6q

By placing r = 1, we get, a = 6q +1

By placing, r = 2, we get, a = 6q + 2

By placing, r = 3, we get, a = 6q + 3

By placing, r = 4, we get, a = 6q + 4

By placing, r = 5, we get, a = 6q +5

Thus, a = 6q or, 6q +1 or, 6q + 2 or, 6q + 3 or, 6q + 4 or, 6q +5.

But here, 6q +1, 6q + 3, 6q +5 are the odd integers.

Therefore, 6q or, 6q + 2 or, 6q + 4 are the forms of any positive even integers.

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Answer 2

Step-by-step explanation:

Let ‘a’ be any positive even integer and ‘b = 6’.

Therefore, a = 6q +r, where 0 ≤ r < 6.

Now, by placing r = 0, we get, a = 6q + 0 = 6q

If r = 1, we get, a = 6q +1

if , r = 2, we get, a = 6q + 2

if r = 3, we get, a = 6q + 3

if, r = 4, we get, a = 6q + 4

if, r = 5, we get a=6q+5

Thus, a = 6q or, 6q +1 or, 6q + 2 or, 6q + 3 or, 6q + 4 or, 6q +5.

But here, 6q +1, 6q + 3, 6q +5 are the odd integers.

Therefore, 6q or, 6q + 2 or, 6q + 4 are the forms of any positive even integers.