show that every odd number can be expressed an a difference of two consecutive squares
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Let two consecutive numbers be n and (n+1),
∴Their squares are, n² and (n+1)²
Difference=n²+2n+1-n²
=2n+1, which is any odd number
∴Their squares are, n² and (n+1)²
Difference=n²+2n+1-n²
=2n+1, which is any odd number
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