Question

Show that every odd positive integers is of the form 2m+1,w here m is some integer

Answer 1

let b=3 and a be any positive integer
a=bq+r

let r=0
a=3q+0
a=3q but it would be even
let r be 1
a=3q+1 which would be odd


sorry you can take m in plave of q

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Answer 2

let'a, be any positive integer n "b"=2 where m is some integers .By using Euclid,s division algorithm a=bm+r where o<r <2 therefore the possible value of r is 0,1 therefore a=2m, 2m+1 in which 2m+1 is a positive odd integers (r=/= 2m)because it is a positive even integer