Math, asked by keerthi3896, 9 months ago

show that every positive even integer is of the form 2q and that every opposite odd integer is of the form 2q + 1 where Q is some integer​

Answers

Answered by dixa34
1

Answer:

you can do it in easy way just like it has one fomula a=bq+r then from this

Step-by-step explanation:

  1. a=2q+r so 0then greater then r then greater then 2. so. a=2q+0. then. a= 2q+2. then a=2q+4 q is a quotient and a is odd integer

and even both they are

Answered by pkpprincekumar121
0

Answer:

let a and b=2 an positive integer

By Euclid division lemma

a=bq+r

Step-by-step explanation:

where r is 0<=r<2, then r=0,1,2etc

when we take r=0 then,

a=2*q+o=2q. .(even) in case1

when we take r=1 then

a=2*q+1=2q+1 (odd) in Case 2

Hence, every positive even integer is of the form of (2q) and every positive odd integer in the form of (2q+1) for some integer Q.

I HoPE u r understand this question thank you

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