show that every positive even integer is of the form 2q and that every opposite odd integer is of the form 2q + 1 where Q is some integer
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1
Answer:
you can do it in easy way just like it has one fomula a=bq+r then from this
Step-by-step explanation:
- a=2q+r so 0then greater then r then greater then 2. so. a=2q+0. then. a= 2q+2. then a=2q+4 q is a quotient and a is odd integer
and even both they are
Answered by
0
Answer:
let a and b=2 an positive integer
By Euclid division lemma
a=bq+r
Step-by-step explanation:
where r is 0<=r<2, then r=0,1,2etc
when we take r=0 then,
a=2*q+o=2q. .(even) in case1
when we take r=1 then
a=2*q+1=2q+1 (odd) in Case 2
Hence, every positive even integer is of the form of (2q) and every positive odd integer in the form of (2q+1) for some integer Q.
I HoPE u r understand this question thank you
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