Show that every positive even integer is of the form 2q, and that every positive odd integer is of the form 2q+1, where q is some integer.
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Answered by
20
Let a be any positive integer and b=2. Then, by Euclid's division lemma there exist integers q and r such that
a = 2q + r , where 0 = r < 2
now, 0 = r <2
=> 0= r= 1
=> r=0 or, r=1 ( because r is an integer)
therefore a =2 q, then a is an even integer.
we know that an integer can either be even or odd. Therefore any odd integer is of the form 2q +1.
a = 2q + r , where 0 = r < 2
now, 0 = r <2
=> 0= r= 1
=> r=0 or, r=1 ( because r is an integer)
therefore a =2 q, then a is an even integer.
we know that an integer can either be even or odd. Therefore any odd integer is of the form 2q +1.
Answered by
33
Hey sister !!!
here is your answer !!!
Let a be any positive integer and b =2
then by EDL ( eculid division leema )
there exist integers q and r
a = 2q + r. { where r is an integer }
now ,
0≤ r < 2
hence the number exist in form of
a = 2q
and a= 2q + 1
if a= 2q , where a is even integer
and a = 2q+1 , where a is odd integer .
=============
hope it helps you sister !!!
thanks
here is your answer !!!
Let a be any positive integer and b =2
then by EDL ( eculid division leema )
there exist integers q and r
a = 2q + r. { where r is an integer }
now ,
0≤ r < 2
hence the number exist in form of
a = 2q
and a= 2q + 1
if a= 2q , where a is even integer
and a = 2q+1 , where a is odd integer .
=============
hope it helps you sister !!!
thanks
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