show that every positive even integer is of the form 2q and every positive odd integer is of the form 2q+1 where q is some integer [from real number]
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Using division lemma,
n=bq+r
n being any no.
n=2q+0
if q is odd then 2*odd is always even and 2*even is always even
n=2q+1
As, mentioned above 2q is always even so even + 1 should be odd.
Hope it helps.
If it does Mark as BRAINLIST.
n=bq+r
n being any no.
n=2q+0
if q is odd then 2*odd is always even and 2*even is always even
n=2q+1
As, mentioned above 2q is always even so even + 1 should be odd.
Hope it helps.
If it does Mark as BRAINLIST.
Answered by
0
To Show :
Every positive odd integer is of the form 2qbabr that every positive odd integer is of the form 2q+1, where q € Z .
Solution :
Let a be any positive integer.
And let b = 2
So by Euclid's Division lemma there exist integers q and r such that ,
a = bq+r
a = 2q+r (b = 2)
And now ,
As we know that according to Euclid's Division Lemma :
0 ≤ r < b
Here ,
0 ≤ r < 2
Here the possible values of r are = 0,1
=> 0 ≤ r < 1
=> r = 0 or r = 1
a = 2q+0 = 2q or a = 2q+1
And if a = 2q , then a is an integer.
We know that an integer can be either odd or even.
So , therefore any odd integer is of the form 2q+1.
#Hence Proved
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