Question

Show that every positive integer is either every or odd.

Answer 1

because integers start from-1 to positive digits

Answer 2

$\huge\fbox\red{A}\fbox\pink{n}\fbox\purple{S} \fbox\green{w}\fbox\blue{E}\fbox\orange{r}$

For example, 'n = 2k + 1', where 'k' is an integer, then, (n +1) = (2k+1) + 1. And after simplifying the brackets, we get (2k +2), which is divisible by 2. And as (2k+2) is divisible by 2, it must be an even number, because only even numbers are a multiple of 2.