Show that every positive integer is every or odd
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integers are in form of p/q so q not equal to 0 .....
in positive integers having all natural numbers....so add & even numbers are including in this integers..so we can say every positive integer is every odd ...
in positive integers having all natural numbers....so add & even numbers are including in this integers..so we can say every positive integer is every odd ...
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Step-by-step explanation:
let us assume that there exist a small positive integer that is neither odd or even, say n.
Since n is least positive integer which is neither even nor odd, n - 1 must be either or or even.
CASE 1 :
If n - 1 is even , then n - 1 = 2m for some integer m .
But , => n = 2m + 1 .
This implies n is odd .
CASE 2 :
If n - 1 is odd , then n - 1 = 2m + 1 for some integer m .
But, => n = 2m + 2 = 2( m + 1 ) .
This implies n is even .
In both cases , there is a contradiction .
Thus , every positive integer is either even or odd .
Hence, it is solved
THANKS
#BeBrainly.
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