Math, asked by Vijayrcb, 1 year ago

Show that every positive integer is every or odd

Answers

Answered by prashanth997
0
integers are in form of p/q so q not equal to 0 .....
in positive integers having all natural numbers....so add & even numbers are including in this integers..so we can say every positive integer is every odd ...
Answered by Anonymous
3

Step-by-step explanation:


let us assume that there exist a small positive integer that is neither odd or even, say n.


Since n is least positive integer which is neither even nor odd, n - 1 must be either or or even.


CASE 1 :


If n - 1 is even , then n - 1 = 2m for some integer m .


But , => n = 2m + 1 .


This implies n is odd .


CASE 2 :


If n - 1 is odd , then n - 1 = 2m + 1 for some integer m .


But, => n = 2m + 2 = 2( m + 1 ) .


This implies n is even .



In both cases , there is a contradiction .


Thus , every positive integer is either even or odd .



Hence, it is solved



THANKS



#BeBrainly.


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