Question

show that every positive odd integer is of the form 4q + 1 and 4q + 3

Answer 1

Answer:

As per Euclid's Division Lemma

If a and b are two positive integer, then

a=bq+r

where 0<r<b

Let positive integer be a

and b= 4

Hence a= 4q+r

where 0<r<4

r is an integer greater than or equal to zero and Less than 4

Hence r can be either 0,1,2,3

Step-by-step explanation:

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Answer 2

Here is your answer.

Hope it helps!

Here, Euclid 's Division lemma is used ...